Nice to meet you everyone.
I’m an engineer of Korea, working on image object recognition.
Any help (especially about my English translation) would be welcomed.
pilhoon-at-gmail-dot-com

2013년 6월 4일 화요일

inverse matrix's eigenvalue

\(A\mathbf{v} = \lambda\mathbf{v} \implies A^{-1}A\mathbf{v} = \lambda A^{-1}\mathbf{v}\implies A^{-1}\mathbf{v} = \frac{1}{\lambda}\mathbf{v}\)

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